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#### 35 comments :

1. The net electrical charge of the semiconductor material is zero.

2. Question no. 35
ans. 1

3. Part B
probability ans 2/9
distance betwetn latice plane ans 4 A
resistor ratio ans N^2
angle of refractd beam ans 56.7
Rms error 3.3%
period of pendulum ans 2T/sprt5
ground state of 5 identical particles 5hw
orthogonal ans -exp(-i phi) cosx +sinx
N.N matrix ans one eigen value N Other 0
canonical pair ans q2,-p2
wave fn ans parity operator
efficency ans 1
electic fild for r>R ans -BR2/2r theata
PART A
electic fild ans -vB(14j+7k)
integral ans e-1/e
temp aftr compres ans 887
series converges to pi/4
magnetic field in othr inertial frame E2=B2
Change in entropy ln(T1+T2/2SQRT(T1T2))

4. ********three mark question*******

consider a particle of mass m moving inside a two-dimensional square box: ans-(c)5(hcut)^2/(2mL^2)

a monoatomic ideal gas at 17 degree: ans- (d) 887 degree

an observer in an inertial frame finds that: ans- (b) E.B= 0

a magnetic field B=B0(i+2j-4k): ans-(d) E=-v0B0(14j+7k)

define (sigma)x = (f'+ f) & (sigma)y = (f'- f): ans-(b) 2f'f-1

an electric in a region is given by E(x,y,z): ans-(c) 13,1,6

consider an ideal gas of mass m at temperature T1: ans-(a)

consider the bohr model of the hydrogen atom: ans-(d)

********one mark question******

the ground state energy of 5 identical spin-1/2: ans-(b)

efficiency of perfectly reversible: ans- (d) 1

a point charge +q placed at (0,0,d): ans- (d)

what is the value of the series: ans-(d) 1

the second order maximum in the diffraction: ans-(c) 4 Ang

the spatial part of a two-electron state: ans-(c)

the ratio of maximum to minimum resistance: ans-(b)

the wave function of a free particle in one dimension: ans-(d)

the net charge of a n-type: ans-(b)

the length and radius RMS error: ans-(a)

when unpolarised light is incident: ans- (a)

if the co-ordinate q and the momentum p : ans-(c)

the quantum state sin x... : ans-(d)

the binding energy of positronium: ans-(a)

for an N*N matrix: ans-(d)

an unbiased die : ans-(b)

a cube has a constant electric pot. V : ans-(a)

a girl measures the period of simple pendulum: ans-(c)

a sodium atom in the first excited...corresponding line-width: ans-(b)

consider a particle of electric charge e... its trajectory: ans-(a) or (c)

5. R series..
3. d
5. d
9. c
10. a
12. b
14. c
16. c
17. c
20. b
22. 0
24. a
25. d
26. c
27. c
29. b
30. d
31. d
32. b
34. d
35. a
36. d
37. b
39. b
42. c
43. d
45. d
47. b
48. a
49. a
50. c

6. R series..
3. d
5. d
9. c
10. a
12. b
14. c
16. c
17. c
20. b
22. 0
24. a
25. d
26. c
27. c
29. b
30. d
31. d
32. b
34. d
35. a
36. d
37. b
39. b
42. c
43. d
45. d
47. b
48. a
49. a
50. c

7. PLEASE dont just tell the question no and the key since there are the series of booklet. It is better to tell the answer with some hint.

8. please do not post according to question no. because there are three sets available...try to mention questions..

9. Set p

5.d
6.c
10.d
12.a
13.c
14.c
17.c
18.b
20.a
22.b
25.a

27.b
28.d
29.d
31.c
32.b
33.d
34.d
35.d
36.c
39.c
42.b
43.c
44.b
48.a
49.d
50.d

any corrections . Pls comment on this key

1. Anonymous11 July, 2014

answer of 34 is not correct...the answer is c..that is magnitude of the field is zero,,,,,

10. series R 3D,9D,10B,14C,17C,19B,25D,31D,34C,35B(NT SURE),37B,44A,47B,48C,49C..PLZ CHECK N CORRECT IF RQURD.

11. ans for Q-set jest-19th feb 2012
2)a (May Be)
4)d
5)c (May Be)
6)c
9)d
10)c (May Be)
11)a
15)a
19)c
20)b
21)a
22)b
23)a
27)b
28)d
29)c
30)d
33)c
34)b
35)d
37)c
38)c
39)b
41)b
43)b
46)c
47)d
49)d

12. Q49 ANSWER IS d series q

13. Question no. 27
ans. C

no.31
ans. C
no. 32
ans. B
no.34
ans. A
no. 36
ans. C
no.40
ans. B
no.42
ans. C
no.44
ans. C
no. 49
ans. D

14. QUESTION NO. 1
ANS. 887
QUESTION NO. 2
ANS. E.B=0
QUESTION NO. 4
ANS. X2/2-SQRT(2)XTANH(SQRT(2)X)
QUESTION NO. 5
ANS. E=-VoBo(14j+7k)
QUESTION NO. 6
ANS. BECOMES APERIODIC
QUESTION NO. 7
ANS. Rf=Ro/2
QUESTION NO. 10
ANS. ac
QUESTION NO. 11
ANS. 3h2/2ML2
QUESTION NO. 12
ANS. 2mCpln(T1-T2)/2SQRT(T1T2)
QUESTION NO. 13
ANS. 0.9c
QUESTION NO. 17
ANS. 45,6,1
QUESTION NO. 18
ANS. 1
QUESTION NO. 20
ANS. INFINITE
QUESTION NO. 23
ANS. Vo/2(1-EXP(-t/2RC))
QUESTION NO. 24
ANS. ONVERGES TO UNITY
QUESTION NO. 25
ANS. h=k=l
QUESTION NO. 26
ANS. MOVES WITH A CONSTANT DECELERATION
QUESTION NO. 28
ANS. 1
QUESTION NO. 32
ANS. N2
QUESTION NO. 33
ANS. HAMILTONIAN
QUESTION NO. 34
ANS. q/16PIEoD2
QUESTION NO. 35
ANS. 1
QUESTION NO. 36
ANS. 4 A
QUESTION NO. 40
ANS. ZERO
QUESTION NO. 41
ANS. 3.3%
QUESTION NO. 42
ANS. 23.3
QUESTION NO. 43
ANS. >>300K
QUESTION NO. 44
ANS. 1/9
QUESTION NO. 45
ANS. 0
QUESTION NO. 46
ANS. 2T/SQRT(5)
QUESTION NO. 48
ANS. 13.6/2
QUESTION NO. 49
ANS. ONE EIGEN VALUE=N, THE OTHER=0
QUESTION NO. 50
ANS. 1.7 * 10(6) HZ

15. anybody have computer science answer key....

16. @Anonymous

qn 50 of p series ans is"b"

17. vishal sir,23 17 etc are correct?? i think dey need correction.:(

18. @evan

hello evan ,
please check quest. 39 of r series booklet....unpolarised light....
its answer is (b) 33.4 degree
not 56.7 degree
please give me a hint about quest. 4 (changes sign underexchnage of x & y)
, quest. 29 (ground state of harmonic oscillator)
quest 38(rms error)

urs all other questions are perfect.
best of luck

19. @prashant
sir can u jst cmment on q2,18,22,10,24,23 set r.. plzz

20. anyone set r,perfect answers for part b q28,26,46,48..

21. @prashant for one dimensional harmonic oscillator he has given 5 particles and he said spin - 1/2
so they are fermions
he has not mentioned the spin state
so 2 particles for one state so,
(2hw/2+6hw/2+5hw/2)=13hw/2

22. @Anonymous
ques (2) entropy of the system (a)
ques (10) simple pendulum (c)
ques (23) infinte series (c)
ques (24) bcc crystal (a)

23. @Anonymous
set r
(28) small magnet(a)
(46) debye temp. (a)
(48) potential of cube (a)

24. can anyone answer the question 25 of set Q in which we have to find the entropy of a two level system with energy E1 and E2 each with degeneracy g1 and g2 , and probability p1 and p2

25. series R
Q1...(b)
Q3...(d)
Q4...(c)
Q5...(d)
Q6...(b)
Q7...(d)
Q9...(c)
Q10...(b)
Q12...(b)
Q14...(c)
Q15...(a)
Q16...(c)
Q17...(c)
Q21...(b)
Q22...(a)
Q23...(c)
Q24...(a)
Q26...(a)
Q27...(c)
Q28...(d)
Q29...(d)
Q30...(d)
Q31...(d)
Q33...(c)
Q34...(c)
Q36...(d)
Q37...(b)
Q39...(a)
Q40...(c)
Q42...(c)
Q43...(d)
Q44...(a)
Q45...(d)
Q46...(a)
Q47...(a)
Q48...(a)
Q49...(c)

26. megharaj

all the ans quoted here for spatial part of two-electron state is (c) which wrong, correct ans is (d) becoz itz a symmetric state.

27. Can anyone please tell me that when is the result expected & hw much marks is the good enough to get admission..kindly tell soon

28. @Nagendra Shiwakoti Ans to probability question is 1/9 because they ask for positive diff. between two numbers.

29. SET- R

Q.No
1:- ( )
2:- ( )
3:- (D)
4:- (C)
5:- (D)
6:- ( )
7:- ( )
8:- (B), here put value of w.f. in S.E. and take energy as additive constant.
9:- (D), Since F= q(E+v*B)=0 => E=-(V*B).
10:- ( )
11:- ( )
12:- (B)
13:- (C)
14:- (C), Since for Electrostatic field Curl of E = 0
15:- (A)
16:- (C), (5/V)=5micro Sec/Sqrt(1-V^2/C^2)
17:- (C)
18:- ( )
19:- (B)
20:- ( )
21:- ( )
22:- (A)
23:- (C)
24:- (A)
25:- (D), First reduce the circuit using thevenin's theorem after that solution is straight forward.
26:- (C), Electic force >>>> gravitational force.
27:- ( )
28:- ( )
29:- (D), fill up to n=4 energy levels because H.O energy levels are non degenerate.
30:- (D), Efficiency= 1-T2/T1 and t2=0 here.
31:- (D)
32:- (D), A2-B2=(A-B)(A+B) then first term becomes exp(X) & 2nd term becomes exp(-X).
33:- (C)
34:- (C)
35:- (B)
36:- (D)
37:- (B)
38:- ( )
39:- ( )
40:- ( )
41:- ( )
42:- (C)
43:- (D)
44:- (A)
45:- (D)
46:- (A)
47:- (A)
48:- (A)
49:- (C)
50:- ( )

30. Latest answer key with question paper http://physics43.files.wordpress.com/2012/03/jest-2012-question.pdf

31. The JEST 2012 Question paper and answer key for the JEST 2012 (e.g P-series) is available for verification.

If you have any objection on the published answer key, please write to jest12 @physics .iisc. ernet. in with valid arguments before 10.00 am on or before 5th March 2012."

32. The JEST 2012 Question paper and answer key for the JEST 2012 (e.g P-series) is available for verification.

If you have any objection on the published answer key, please write to jest12 @physics .iisc. ernet. in with valid arguments before 10.00 am on or before 5th March 2012."

33. http://physicskerala.blogspot.in/2011/03/jest-2011-results-published-at.html

34. results are expected to be on 16th of this month
and the cut off may be 30
and to get admission one must get a rank below 150

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