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CSIR UGC NET, 2013 June 23, Detailed Answer Key, Key, Answers, solutions, Explanations, Comment Here

►CSIR UGC NET, 2013 June 23, Detailed Answer Key, Key, Answers, solutions, Explanations, Comment Here

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UGC CSIR NET 2013 June 23 Physics Answer Key Comment here with explanation
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238 comments:

  1. section-c
    degrees of freedom of rigid body in 6-Dspace
    A,B,C. are spin half particles....possible spin of d when A=B+C+D
    expectation value of Lx^2+Ly^2 for a wave function
    digital electronics ans A

    ReplyDelete
    Replies
    1. i think expectation value will be 2h^2

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    2. This comment has been removed by the author.

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    3. This comment has been removed by the author.

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    4. for rigid body, whatever be the dimensions it always have always 6 degrees of freedom

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    5. liquid's height is is 3h/2

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    6. Booklet B
      Q-75
      correct ans is A
      Velocity and pressure is More than std and Humidity and temp is lesser.

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    7. density of state D(E) is proportional to Energy E.

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    8. This comment has been removed by the author.

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    9. how 70, please help me, ii got 56

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    10. harris how to get 70 rectangles pls explain..

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    11. count the number of rectangles using different combinations. eg.,1X4,4X1,2X4,4X2,3X4,4X3,etc. the total number will come to 70.

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    12. # of degrees of freedom of a rigid body in d space dimension = d(d+1)/2
      Part-C digital electronics question option 1 is correct
      in a given problem gates are NOT , NOR , OR and output is VP+TH so 0x0 + 1x1 = 0+1 = 1

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  2. section A
    square pyamid to b costructed using threadsin single strand...min cuts==3
    largest number=3^100

    ReplyDelete
    Replies
    1. square pyramid ans is 1

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    2. yes largest number is 3^400

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    3. how to u got one in pyramid question pls give to detailed answer...

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    4. Option 2 is correct
      a^mn = (a^m)n 2^5=32 3^4=81 4^3=64 5^2=25 3^400 is the largest #

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    5. i also mark 1 for pyramid bt i think it must be 7.....
      bcoz 4 for lower base parts of rectangle nd 3 for above ...so it must be 7....

      Delete
  3. 10^18 was answer of one ques of section a...no of nanoplates
    Ms white was wearig black dress
    childcare facility...Answer A...only ratio can be calculated

    ReplyDelete
    Replies
    1. please give me reason for 10^18

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    2. This comment has been removed by the author.

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    3. 2nd and 3rd one are correct

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    4. 10^18 is right.. 1000nm3 is not equal to 10^-7cm3.it is cm3 not cm.(1000nm=1000*10^-7*10^-7*10^-7cm3)

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    5. For child care facilities, none can be answered, as if we don't take survey on weekend, how can one get ratio for men and women in general??

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    6. 10^18 option is correct 1 cm^3= 10^-6 m^3 and 10X20X5 nm^3=1000X10^-27 m^3=10^-24 m^3
      # of unit cells=10^-6 / 10^-24=10^18
      Ms Brown dress was White Ms Black dress was Brown Ms White dress was Black Option 3 is correct

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  4. series problem in section A: correct ans is 1

    ReplyDelete
    Replies
    1. Option 2 is correct answer is 1
      (2-1)/1X2 + (3-2)/2X3 +(4-3)/3X4 + .......=1-1/2+1/2-1/3+1/3-.........-1/infinity=1+0=1

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    2. This comment has been removed by the author.

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  5. This comment has been removed by the author.

    ReplyDelete
    Replies
    1. CSIR UGC NET, 2013 June 23, Detailed Answer Key, Key, Answers, solutions, Explanations, Comment Here

      Delete
    2. Are you sure your ans is correct as u given it ? have u cross checked.

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    3. Dear check your answers:
      Sec C: 46. B, 48. B, 52. A, 54. B, 59. D, 60. C, 64. B, 70. C, 75. A

      Sec B: 26. A, 31. A, 33. C, 35. B, 39. C, 41. A

      Delete
  6. This comment has been removed by the author.

    ReplyDelete
    Replies
    1. some are matched with this but some r not but m not 100% sure may be u r right how much u r sure about your answer

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    2. Three questions from section C,1 each from A and B are incorrect i think.

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  7. please send answer key of booklet A

    ReplyDelete
  8. for booklet A
    PART B
    26-2, 27- 2, 31-1, 33-3, 34-3, 40-1, 41-1, 42- 4, 44-1,

    PART C
    46-1, 47-2, 48-4, 50-1, 53-3, 58-1, 59-1, 61-3, 64-1, 68-3, 73-3, 75-3

    ReplyDelete
    Replies
    1. for booklet A
      PART B
      21-3, 22-2, 24-1, 25-1, 26-2, 27-2, 31-3, 34-3, 39-4, 41-4, 44-1

      PART C
      46-1, 48-4, 51-2, 54-1, 56-1, 57-4, 58-1, 59-1, 62-3, 65-2, 71-3, 73-4

      PART A
      20-4, 19-4, 16-3, 15-2, 14-3, 7-1, 6-3, 3-4, 2-2, 1-1

      Delete
    2. for booklet A
      7)2 14)4 16)3 18)2 19)4 20)4
      23)3 24)4 26)3 27)2 34)1 36)4 39)4 42)2 44)1
      46)1 52)2 54)4 56)2 59)4 61)3 62)4 64)1 65)2 73)4 75)3

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    3. I feel 3-4 bits may be wrong that's it, except that everything is ok.

      Delete
  9. Booklet B
    Section A
    River flow will b downward i.e., South will b right answer.

    ReplyDelete
    Replies
    1. yes south cos river's downsteam is from higher altitude to lower

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    2. but asked for direction of downstream water, if its south water must go into earth

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    3. Arey baba...!!!

      The direction shown in the graph was for surface of earth...!!
      And not for the height...!!!:-D

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  10. All path will be of same distance to reach from A to C

    ReplyDelete
    Replies
    1. The total distance travelled by a person is same for 2 paths

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  11. for density of states it is constant for 2 dimensional fermi gas and for three dimensional
    fermi gas proportional to (E)^1/2

    ReplyDelete
    Replies
    1. for 1-D it is proportional to 1/(E^1/2)
      for 2-D it is ----------- E
      for 3-D E^1/2

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    2. density of states of a electron gas in 2 dimension is independent of energy so option 4 is correct

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  12. Survey
    Option A can be answered only..
    Weekend data can not be estimated from that information

    ReplyDelete
    Replies
    1. yes its correct, only A can be estimated

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  13. question for section c: expectation value of Lx^2+Ly^2 is 26hcut^2/25

    ReplyDelete
  14. 3 power 400 and Density states constant , 100 rectangle, h/4 , independent of path...

    ReplyDelete
  15. what is the equilibrium temperature ?

    in rest frame area of disk is : (1-v^2/c^2)^-1

    ReplyDelete
    Replies
    1. P1V1+P2V2/p1v1/t1+p2v2/t2
      (1-v^2/c^2) i think
      no of rectangles is 100

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    2. ice water temprature-0 degrees cos 800cal required by ice to melt while water gives 775 cal

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    3. @ vineet pannu, can u explain how it is P1V1+P2V2/p1v1/t1+p2v2/t2
      I also filled same choice but dont know the explanation.

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    4. 10X80+10X1X(t-0)=30X1X(25-t) 8+t=75-3t 4t = -5 t = -1.25 0C

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  16. for expectation value, we have to write Lx^2+Ly^2= L^2-Lz^2
    answer is 26*hcut^2/25

    ReplyDelete
  17. temperature at eqlm: is -1.25 °C.

    ReplyDelete
  18. increase in height of liquid in cylindrical vessel is : R/12

    increase in volume of water=volume of immersed part of sphere

    pi*R^2*dH = (4/3*pi*(R/2)^3)/2 (since half of sphere is immersed )

    so dH (increase in height of level of water)= R/12

    ReplyDelete
    Replies
    1. Your procedure is exactly correct so correct option is 4 i.e. R/12

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  19. maximum area of triangle that can inscribed in semicircle is :

    =1/2*height*base
    where, height = radius of semi circle
    base = diameter of circle


    finally,
    1/2*R*2R

    answer is R^2 ....option b


    ReplyDelete
    Replies
    1. For maximum area of triangle that canbe inscribed in semicircle is isosceles right angle triangle
      so area = 1/2 X 2R X R = R^2 option 1 is correct

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  20. probability of some of 2 numbers selecting from 1-15

    (5,15)=(15,5)
    (6,14)=(14,6)
    (7,13)=(13,7)
    (8.12)=(12,8)
    (9,11)=(11,9)
    total is 10
    but number of ways we can arrange 2 numbers from 15 is 15P2 = 210

    probability is = 10/210 = 1/21

    ans = 1/21

    ReplyDelete
    Replies
    1. (5,15) (6,14) (7,13) (8,12) (9,11)
      # favorable events=5 and total # of events= 15 C 2 = 105
      required probability=5/105=1/21 so option 2 is correct

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  21. differential equation is dx/dt=x^2 or 2dx/dt=x^2 in part B?

    pls let me know ?

    ReplyDelete
    Replies
    1. it ws dx/dt=x^2

      but i dnt knw ans...!:-D:-p

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    2. dx/x^2=dt -1/x=t+c x(t) = -1/(t+c) x(0)=-1/(0+c)=1 so c=-1
      x(t) = -1/(t-1) If t tends to 1 then x will be blow up so option 1 is correct

      Delete
  22. diff eqn for langrangian ques?
    -t^2/2m+c1t+c2

    ReplyDelete
    Replies
    1. for lagrangian problem answer is -bt^2/2m + c1t + c2 by using generalized momentum and its derivative

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  23. What is the answer for the question, in which they asked about survey for health care service (23% men's and rest are women's???)???

    ReplyDelete
    Replies
    1. choice A-only A can b answered

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    2. ya but its not necessary that all the people participated in the survey, who came to the mall, then how we can tell the ratio of men's and women's in the mall??

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    3. Only option A can be answered..
      Option B cnt be cz of insufficient data..

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  24. What will b the ans of wavelength analog of layman series

    ReplyDelete
  25. 1/(1*2)+1/(2*3)+1/(3*4)+.....infinity what will b it's ans?

    ReplyDelete
    Replies
    1. I haven't done it in the exam but it will be 1.

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    2. Its a 1..!
      Cz 0.5+0.166+0.083+0.05+0.033+0.0239+.....=1

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    3. nth term Tn = 1/(n*(n+1)) = 1/n - 1/n+1.

      Series Sum= (1/1 + 1/2 + 1/3 +.....) - (1/2 + 1/3 + 1/4 +....) = 1 (only first term of first series)

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  26. can any one submit the key for booklet C

    ReplyDelete
    Replies
    1. first u provide then i cross check it ,in physical science

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    2. part A- of booklet C
      can any one help me with the correctness of my answers, thanks in advnace
      1.i did not answer, 2.1 3.1 5.3 6.3 7.4 8.2 10.4 12.3 13.1 14.3 `15.4 16.4 17.3
      19.2 20.2

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  27. for booklet A
    PART B
    21-3, 22-2, 24-1, 25-1, 26-2, 27-2, 31-3, 34-3, 39-4, 41-4, 44-1

    PART C
    46-1, 48-4, 51-2, 54-1, 56-1, 57-4, 58-1, 59-1, 62-3, 65-2, 71-3, 73-4

    PART A
    20-4, 19-4, 16-3, 15-2, 14-3, 7-1, 6-3, 3-4, 2-2, 1-1

    ReplyDelete
  28. dx/dt= x^2 as x(0)=1,ans is infinity

    ReplyDelete
    Replies
    1. its answer is one. First integrate the function and then find the integration constant using initial condition

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  29. questions are available in csir website

    ReplyDelete
    Replies
    1. This comment has been removed by the author.

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    2. yes question papers are now available on csir web but physics paper is not uploaded very properly.
      Some part of questions are missing in the scanned version of the paper

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  30. HERMITE FUNTION ANSWER H4(0)=12

    ReplyDelete
    Replies
    1. hermite function explain plz

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  31. dx/dt=x^2
    -1/x=t+c
    f(0)=1;
    c=-1
    x=-1/(t-1)
    so...when t-----1.....x ----infinity..... blow up

    ReplyDelete
  32. I think in my question booklet (CODE B) was missing. Because in WKB method delta function potential (from PART C) is very famous problem to me. Also I have read the question paper very well especially PART-C. Is there any way too check my question paper again?

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  33. This comment has been removed by the author.

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  34. This comment has been removed by the author.

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  35. Csir kept all question papers on main website, but physics paper was not properly scanned.You will better go through the chemistry paper for aptitude (SECTION-A) part.

    ReplyDelete
    Replies
    1. thx srinu, how is IIIT

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    2. it is good,do u know about 3it?

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    3. i know, 3it, i know ur campus, i even know ur director, Ibrahim khan

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  36. Booklet B of Physics (Or Booklet A of chemistry):
    Sec-A: 1.C, 2.A, 4.C, 5.A, 7.D, 8.D, 9.D, 10.A, 11.B, 12.C, 14.C, 15.D, 18.B, 19. D

    ReplyDelete
    Replies
    1. Booklet B: For Sec-C, Please correct me if I am wrong:
      46. B, 48. B, 52. A, 54. B, 59. D, 60. C, 64. B, 70. C, 75. A

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    2. Any one can query me for any answer of Sec-A I mentioned here.
      and also for SEc B and C if he remember the question(s)

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  37. This comment has been removed by the author.

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  38. IN SECTION B THE CONVERSION TIME FOR THE ADC CONVERTER IN REMAINS UNCHANGED

    ReplyDelete
    Replies
    1. its remain unchanged..
      Cz in SAR, input voltage has nothing to do with Conversation time...!

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    2. YES, Right choice. It will be unchanged because conversation time is characteristics of ADC/DAC. it does not depend upon input/output

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    3. ohhh TY, even i answered it as unchanged, but i was in little confusion

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  39. any one have booklet c answer in physical science

    ReplyDelete
  40. Can any answer that question, with proper logic?
    A=B+C+D

    ReplyDelete
  41. Booklet A, Q.31, relativistic motion of a disk,
    Solution: key concept in the question is in relative motion, distance only in one dimension (say length or width) will be reduced by factor of [(1-u^2/v^2)]^1/2. so area will also be reduced with same factor. Ans is (1).

    ReplyDelete
    Replies
    1. very right!!!!didnt think in tat way....

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  42. Any detailed ans for Q.64 Booklet-A ?
    if A and B satisfy coomunication relation [A,B] = I, then
    (i) [eA,B] = eA
    (ii) [eA,B] = [eB,A]
    (iii)[eA,B] = [e-B,A]
    (iv) [eA,b] = 1
    Please post here

    ReplyDelete
    Replies
    1. option ii, as identity valids

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    2. option ii, as identity valids

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    3. @ kissy, Can u please explain the validation of identity in option II

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    4. Option 1 is correct
      [ f(A), B ] = [ A, B ] F'(A)

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    5. how option 1 is correct murty b

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    6. its e^A I did it in exams.
      expand e^A as 1+A+A^2/2!+....... and then solve we get answer a option

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  43. I have talked at CSIR, they said they will upload a new copy of scanned physics paper by tomorrow evening.

    ReplyDelete
  44. Capacitance in the parallel wires of 4cm diameter separated by distance 2m (as I remember) is 88.5 nF, I think.
    Correct me if it is wrong.

    ReplyDelete
  45. what about stable isobar ans??

    ReplyDelete
  46. Plz friends check my Booklet A-part C ans: 48-4,50-1,53-3,54-3,61-3,64-4,65-2,72-2,73-2.

    ReplyDelete
  47. what was the answer of drude model question?

    ReplyDelete
  48. what will be the cut off hey guys

    ReplyDelete
  49. This comment has been removed by the author.

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  50. Booklet Code A (Find it on CSIR site)

    PART-A
    Q1: Ans (4) [154]
    Q2: Ans (4) [R/12]
    Q4: Ans (2) [1]
    Q5: Ans (2) [3h/2]
    Q6: Ans (1) [R^2]
    Q7: Ans (2) [3^400]
    Q10: Ans (3) [436]
    Q12: Ans (3) [R+Rtan]
    Q14: Ans (3) [Ms. White's dress was black]
    Q15: Ans (2) [1/21]
    Q16: Ans (3)
    Q19: Ans (4) [380]


    PART-B
    Q22: Ans (1) [0 C]
    Q24: Ans (1)
    Q31: Ans (1)
    Q36: Ans (4) [1/3 & 2/3]
    Q37: Ans (1) [b2=0 & b1=1]
    Q40: Ans (1) [12]
    Q41: Ans (4) [b=a]
    Q44: Ans (1)


    PART-C

    Q46: Ans (3) [0,0,0] E=-del(-xyz)-d/dt(iA1+jA2+kA3)
    =(iyz+jxz+kxy)-(iyz+jxz+kxy)
    = i*0+j*0+k*0

    Q48: Ans (4) [26h_cross^2/25]
    Q49: Ans (2) [Check Dimension]
    Q53: Ans (3) [See Griffith Q.Mech]

    Q54: Ans (2) [If spin degeneracy is considered. Two fermions with (+-)1/2 spin can stay with E0 energy]
    Ans (1) [If spin degeneracy is not considered. Only one fermion in each state]

    Q56: Ans (4) [Put it in the equation]

    Q59: Ans (1) [1] After integrating and using condition you will get x(t)=1/(1-t)

    Q61: Ans (3) [t-1+e^(-1)] Find Laplace transform of Ans(3)
    Q62: Ans (3) [d(d+1)/2] Find it on the internet.

    Q65: Ans (4) [a=-2 & b=3] Use Hamilton's eqn of motions. Then,d/dt(Px-3y)=0 & d/dt(P_y+2x)=0

    Q73: Ans (4) [Constant]

    ReplyDelete
    Replies
    1. from where u got it

      Delete
    2. I got it from calculations & discussions of/with me and my friends.
      I hope all answers are correct.

      Delete
    3. Hey For Q no 49 Ans should be option (3). Check the Dimension again. Option (2) will have s^-1 extra. It won't get cancelled. Check again...

      Delete
    4. If you read the question, then you see : "The rate of total energy radiated per unit area"

      The rate of total energy= Energy per unit time (because of rate)=Power

      So, Power per unit area is to be calculated.

      See Larmor formula of "energy radiated by an accelerating charged particle (wikipedia)".

      Larmor formula gives the total power radiated = Energy radiated per unit time.
      Its dimension= (Charge^2)(Length^-1)(Time^-1). If you divide it by area, then dimension= (Charge^2)(Length^-3)(Time^-1) which gives you energy radiated per unit time per unit area (this is the question of NET) and it matches with option (2).

      Delete
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    8. Correction:

      Q12: Ans(4) [R+Rcot]

      Delete
  51. booklet A

    Q.23 Ans(3): Reason I dont know, please explain if someone knows

    Q.24 Ans (1): As probability distribution and velocity both reduces with increment in temperature, (T1>T2, see question)


    Q.28 Ans(1): conversation time is characteristics of device, does not depend upon input or output.

    Q.29 Ans(2): Use V = V0*exp(-t/RC), put the values given, 15 = 150*exp(-1000/R*5*10^-6) => exp (2*10^8/R) = 10 => 2*10^8/R = 2.303 => R = 10^8 ohm

    Q.31 Ans (1): As length reduction will only take place not width reduction.. Use relativity theory

    Q.41 Ans (3): Use A.B = AB cos = dot product of A and B => [(a^2+b^2+2ab cos 120)]*cos 60 = 2ab+a^2 cos 120 + b^2 cos 120 => 1/2 (a^2+b^2-ab) = 2ab - a^2/2 - b^2/2 => 2a^2 + 2b^2 - 5ab = 0 => a =2b or b = 2a; from teh given options, option C is b = a/2

    ReplyDelete
  52. Booklet A

    Q.52: Ans (3) 2/9 : at any stage (say SA = 1, SB = 1, SC = -1), there are only two other possibilities fpr making SA+SB_SC = invariant, i.e. (SA = -1, SB= 1, SC =1 and SA =1, SB =-1, SC =1) including one condition that it can remain same, total probability of finding above mentioned conditions is: 1/3+ 1/3, including that these events can occur even with probability of 1/3 of total possible conditions, complete probability is 1/3(1/3+1/3) = 2/9

    Q. 58 , Ans (1), It is explained earlier in this forum

    Q. 59, Ans (1), It is also explained earlier in this forum

    Q. 62, Little confusion, as there are number of sources on internet report it 6 also. I went with 6, option B

    Q. 70, Ans (2): as in normal case C = EA/D, use this equation considering area of the wire(s) is length *width = 0.75km * 4cm, you will get the answer (correct me if wrong)

    Q. 73, Ans (3): as it is proportional to E in 2-D, to E^1/2 in 3-D. Though I filled there E^1/2

    Q. 74, I am confused between (3) or (4), I went with (3)


    I have also attempted Q. 64 with ans (2) and Q.56 with Ans (3) dont know these are right or wrong

    ReplyDelete
    Replies
    1. that is Q.75, not Q.74

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    2. from where i can get the exact key..when the official key of csir will be released?/?

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    3. as csir said (the official key),they will provide in the first week of July on csir main website.

      Delete
    4. This comment has been removed by the author.

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  53. no...its 4/9 for Sa+Sb+Sc invarient
    because....
    probability for every S to change to -S is 1/3
    ...........................not to change is 2/3
    there are three outcomes for an event Sa+Sb+Sb=constant(1).
    (1)if all S's will not change, then Sa+Sb+sc=constant
    then probability is = 2/3*2/3*2/3=8/27
    (2)now, if Sa change to -1 and Sc change to +1 then Sa+Sb+sc= constant=1,
    so probability is = 1/3*2/3*1/3=2/27
    (3) next if Sa remains same,Sb change, and Sc change , then probability= 2/3*1/3*1/3=2/27

    so total probability is = (8/27)+(2/27)+(2/27)=12/27=4/9, because three are independent events, so we have to add.............ans is 4/9

    ReplyDelete
  54. degrees of freedom is D*(D+1)/2

    ReplyDelete
  55. COde A
    Sec. B
    21-3, 24-1, 26-2, 32-2, 38-3, 39-4, 42-2, 43-3,

    Sec c..
    49-2, 50-3, 51-2, 54-2, 57-4, 59-1, 63-3, 66-3, 71-3

    ReplyDelete
  56. booklet A) answers
    part c......
    48) 4
    52) 4
    53) 3 (you can check last december paper)
    54) 4
    58) 1
    59) 1
    61) 3
    62) 3
    64) 1
    68) 1
    73) 4
    part b.........

    23) 4
    24) 4
    27) 1
    28) 1
    31) 4
    36) 4
    37) 1
    40 ) 1
    44) 3

    part a..........
    1) 4
    2) 4
    3) 4
    4) 2
    6) 1
    7) 2
    8) 3
    9) 2
    10) 3
    12) 4
    14) 3
    15) 2
    16) 3
    18) 2
    19) 4
    20) 4

    ..........these answers are all 100 % correct......if have guys any queries regarding to my answers pls post here......

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  57. Key for June 2013 JRF/NET exam question papers will be uploaded in the first week of July 2013.

    ReplyDelete
  58. In CSIR NET is there section-wise cutoff or not? Please reply me?

    ReplyDelete
    Replies
    1. cumulative total not section wise

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  59. booklet A:
    section A:
    1-1
    2-4
    3-4
    4-2
    5-2
    6-1
    7-2
    8-3
    9-1
    10-3
    11-3
    12----
    13-1
    14-1
    15-2
    16-3
    17----
    18---
    19-4
    20-4
    expected key

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    Replies
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    2. 9-4 since 60/2=30 60/3=20 60/4=15 60/5=12 60/6=10

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  60. what is the amswer of 25 question in booklet A?

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  61. can some one pot the key for booklet C please

    ReplyDelete
  62. pronab choubey 30 june 2013 what is the answer of 67 question in booklet A

    ReplyDelete

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