tag:blogger.com,1999:blog-8705083632203739705.post2208145781339789075..comments2024-01-08T01:42:56.289+05:30Comments on PHYSICS Information and Links: CSIR UGC NET, 2013 December 22, Question Paper, Download, Key, Answers, solutions, Explanations, Comment HereUnknownnoreply@blogger.comBlogger221125tag:blogger.com,1999:blog-8705083632203739705.post-6166512960170428332014-04-01T12:47:39.546+05:302014-04-01T12:47:39.546+05:30ls cut off will be 73 around and 80 plus jrf ugc, ...ls cut off will be 73 around and 80 plus jrf ugc, 90 plus csir jrf Dr. H Kumarhttps://www.blogger.com/profile/08472971482043989614noreply@blogger.comtag:blogger.com,1999:blog-8705083632203739705.post-18564304726335181622014-03-08T20:44:09.070+05:302014-03-08T20:44:09.070+05:30Physics Answer Key 2013 Dec<a href="http://www.physicskerala.in/search/label/Downloading?q=http://www.csirhrdg.res.in/phyD2013key.pdf" rel="nofollow">Physics Answer Key 2013 Dec</a>Shttps://www.blogger.com/profile/08625054792778496944noreply@blogger.comtag:blogger.com,1999:blog-8705083632203739705.post-59914287944278947972014-03-08T20:12:27.411+05:302014-03-08T20:12:27.411+05:30Hello Friends,
You can check your answers on csir ...Hello Friends,<br />You can check your answers on csir web site. <br />I am getting 71.75 marks what is my chance for LS (physics)? Anyone who can tell the cutoff for June 2013 for LS.ashishhttps://www.blogger.com/profile/18091716461316223358noreply@blogger.comtag:blogger.com,1999:blog-8705083632203739705.post-44101711859851782902014-02-07T22:46:54.962+05:302014-02-07T22:46:54.962+05:301/2+1/pi is correct1/2+1/pi is correctanonymaoushttps://www.blogger.com/profile/11271281384440255084noreply@blogger.comtag:blogger.com,1999:blog-8705083632203739705.post-38832170699747402912014-02-02T19:12:04.542+05:302014-02-02T19:12:04.542+05:30Pendulum one is, 2pi*squreroot(L^2+r^2+2LR/(g(L+R)...Pendulum one is, 2pi*squreroot(L^2+r^2+2LR/(g(L+R)). you can solve using lagrangian methodjoehttps://www.blogger.com/profile/08007724639958615391noreply@blogger.comtag:blogger.com,1999:blog-8705083632203739705.post-86522504807877322892014-01-15T17:24:04.830+05:302014-01-15T17:24:04.830+05:30plz some one explain question no.37 set -c plz some one explain question no.37 set -c Anonymoushttps://www.blogger.com/profile/14621780085227992283noreply@blogger.comtag:blogger.com,1999:blog-8705083632203739705.post-76162071892150764872014-01-10T18:04:37.017+05:302014-01-10T18:04:37.017+05:30booklet C, ques.26. it is not mentioned that the...booklet C, ques.26. it is not mentioned that the three fermions are in the ground state, its asking for the all possible ways, so the answer is (2) 4.Anonymoushttps://www.blogger.com/profile/12805458818608715250noreply@blogger.comtag:blogger.com,1999:blog-8705083632203739705.post-14986183836384175512014-01-10T17:59:37.140+05:302014-01-10T17:59:37.140+05:30it is not mentioned that the three fermions are in...it is not mentioned that the three fermions are in the ground state, (1) two particles in the first state and one particle in the second state, and this configuration has two possibilities for the one particle in the 2nd state with spin up or down, (2) and similarly for the case of two particles being in 2nd state and one particle in the first state.Anonymoushttps://www.blogger.com/profile/12805458818608715250noreply@blogger.comtag:blogger.com,1999:blog-8705083632203739705.post-41155520598888110682014-01-07T08:57:04.549+05:302014-01-07T08:57:04.549+05:30Answer 4 is cottect for question 63 (booklet A ) ...Answer 4 is cottect for question 63 (booklet A ) if two bodies are in direct contact. But here a carnot engine <br /><br /> acts between them. So total entropy always should be zero for reversible cycle (carnot cycle )<br /><br /><br /> So,<br /> <br /> Delta S = Delta S1 + Delta S2 = 0 <br /><br /> integration [ T1, Tf] ( dQ/T) + integration[ T2,Tf] (dQ/T) = 0 <br /><br /> integration [T1,Tf] ( (Cv dT)/T) + integration [T2.Tf] ((Cv dT)/T))= 0 (for both bodies Cv is same )<br /> <br /> that implies<br /> <br /><br /> Cv ln (Tf/T1)+ Cv ln (Tf/T2) = 0 <br /> <br /> Cv ln (Tf/T1) = - CV ln (Tf/T2)<br /><br /> ln ( Tf/T1) = ln (T2/Tf)<br /><br /> Tf/T1 = T2/Tf<br /> <br /> Tf^2 = T1*T2<br /><br /> Tf = sqrt (T1*T2)Anonymoushttps://www.blogger.com/profile/11825640266298198950noreply@blogger.comtag:blogger.com,1999:blog-8705083632203739705.post-44092665447474047512014-01-07T08:55:23.066+05:302014-01-07T08:55:23.066+05:30Answer 4 is cottect for question 63 (booklet A ) ...Answer 4 is cottect for question 63 (booklet A ) if two bodies are in direct contact. But here a carnot engine <br /><br /> acts between them. So total entropy always should be zero for reversible cycle (carnot cycle )<br /><br /><br /> So,<br /> <br /> Delta S = Delta S1 + Delta S2 = 0 <br /><br /> integration [ T1, Tf] ( dQ/T) + integration[ T2,Tf] (dQ/T) = 0 <br /><br /> integration [T1,Tf] ( (Cv dT)/T) + integration [T2.Tf] ((Cv dT)/T))= 0 (for both bodies Cv is same )<br /> <br /> that implies<br /> <br /><br /> Cv ln (Tf/T1)+ Cv ln (Tf/T2) = 0 <br /> <br /> Cv ln (Tf/T1) = - CV ln (Tf/T2)<br /><br /> ln ( Tf/T1) = ln (T2/Tf)<br /><br /> Tf/T1 = T2/Tf<br /> <br /> Tf^2 = T1*T2<br /><br /> Tf = sqrt (T1*T2)Anonymoushttps://www.blogger.com/profile/11825640266298198950noreply@blogger.comtag:blogger.com,1999:blog-8705083632203739705.post-40368333440265120772014-01-05T17:49:19.404+05:302014-01-05T17:49:19.404+05:30What can be cutoff Mark's this time for open c...What can be cutoff Mark's this time for open categoryAnonymoushttps://www.blogger.com/profile/04436583731568320852noreply@blogger.comtag:blogger.com,1999:blog-8705083632203739705.post-57786756614042454892014-01-05T08:15:44.860+05:302014-01-05T08:15:44.860+05:30tb>tc>ta because we know that DS/DE=1/T so a...tb>tc>ta because we know that DS/DE=1/T so at costant curve DS/DE=0 so t is largest at tb<br />Anonymoushttps://www.blogger.com/profile/11654888391835628348noreply@blogger.comtag:blogger.com,1999:blog-8705083632203739705.post-3606929486463613412014-01-04T11:05:41.875+05:302014-01-04T11:05:41.875+05:30no it will be 70-71 for LS and 79- 81 for JRFno it will be 70-71 for LS and 79- 81 for JRFAnonymoushttps://www.blogger.com/profile/01883800528555044399noreply@blogger.comtag:blogger.com,1999:blog-8705083632203739705.post-27886729478452582672014-01-04T10:49:41.938+05:302014-01-04T10:49:41.938+05:30 answer 2 is 100 % correct answer 2 is 100 % correct Anonymoushttps://www.blogger.com/profile/11825640266298198950noreply@blogger.comtag:blogger.com,1999:blog-8705083632203739705.post-48782004838655679092014-01-04T10:47:36.934+05:302014-01-04T10:47:36.934+05:30Answer 4 is cottect for question 63 (booklet A ) ...Answer 4 is cottect for question 63 (booklet A ) if two bodies are in direct contact. But here a carnot engine <br /><br /> acts between them. So total entropy always should be zero for reversible cycle (carnot cycle )<br /><br /><br /> So,<br /> <br /> Delta S = Delta S1 + Delta S2 = 0 <br /><br /> integration [ T1, Tf] ( dQ/T) + integration[ T2,Tf] (dQ/T) = 0 <br /><br /> integration [T1,Tf] ( (Cv dT)/T) + integration [T2.Tf] ((Cv dT)/T))= 0 (for both bodies Cv is same )<br /> <br /> that implies<br /> <br /><br /> Cv ln (Tf/T1)+ Cv ln (Tf/T2) = 0 <br /> <br /> Cv ln (Tf/T1) = - CV ln (Tf/T2)<br /><br /> ln ( Tf/T1) = ln (T2/Tf)<br /><br /> Tf/T1 = T2/Tf<br /> <br /> Tf^2 = T1*T2<br /><br /> Tf = sqrt (T1*T2)<br /><br />so answer is option 3 <br /> Anonymoushttps://www.blogger.com/profile/11825640266298198950noreply@blogger.comtag:blogger.com,1999:blog-8705083632203739705.post-82260265277902716752014-01-04T10:27:10.746+05:302014-01-04T10:27:10.746+05:30your answer is right if it is in the of two bodies...your answer is right if it is in the of two bodies are in direct contact. But here a carnot engine is acts between them. So total entropy should be zero as in the case of reversible process (carnot engine).<br /><br />Delta S= delta S1+delta S2 = 0<br /> = integration [t1,tf] (dQ/t)+integration [t2, tf] (dQ/t) = 0<br /><br /> =integration[t1,tf] (Cv dT/T)+ integration [t2,tf] (Cv dT/T) = 0 (since heat capacity is same = Cv for both bodies)<br /> <br /> = Cv ln( Tf/T1) + Cv ln (Tf/T2) = 0<br /> <br /> that implies <br /> = Cv ln (Tf/T1) = - Cv ln (Tf/T2)<br /> <br /> = ln (Tf/T1) = ln (T2/Tf)<br /> <br /> Tf/T1 = T2/Tf<br /> <br /> Tf^2 = T1*T2<br /> <br /> Tf = sqrt(T1*T2)<br /><br /> Anonymoushttps://www.blogger.com/profile/11825640266298198950noreply@blogger.comtag:blogger.com,1999:blog-8705083632203739705.post-49503499829780654462014-01-03T12:56:13.218+05:302014-01-03T12:56:13.218+05:30what is the correct answer for 75th question???what is the correct answer for 75th question???Anonymoushttps://www.blogger.com/profile/02965568148777132071noreply@blogger.comtag:blogger.com,1999:blog-8705083632203739705.post-89421122862942099822014-01-03T12:52:56.910+05:302014-01-03T12:52:56.910+05:30what is the correct answer for 75th question??what is the correct answer for 75th question??Anonymoushttps://www.blogger.com/profile/02965568148777132071noreply@blogger.comtag:blogger.com,1999:blog-8705083632203739705.post-58693118188912943392014-01-02T22:38:17.974+05:302014-01-02T22:38:17.974+05:30Ya its correct ans is b bar d bar+ bd
Use karnaug...Ya its correct ans is b bar d bar+ bd <br />Use karnaugh map to solve. Digital electronics by floydAnonymoushttps://www.blogger.com/profile/12346555581809277786noreply@blogger.comtag:blogger.com,1999:blog-8705083632203739705.post-68381699814706219202014-01-02T20:16:08.636+05:302014-01-02T20:16:08.636+05:30what is the correct answer of Q.no-61 and 75 of bo...what is the correct answer of Q.no-61 and 75 of booklet code C????explain....Anonymoushttps://www.blogger.com/profile/02965568148777132071noreply@blogger.comtag:blogger.com,1999:blog-8705083632203739705.post-32531242933980586412014-01-02T20:11:59.636+05:302014-01-02T20:11:59.636+05:30This comment has been removed by the author.Anonymoushttps://www.blogger.com/profile/02965568148777132071noreply@blogger.comtag:blogger.com,1999:blog-8705083632203739705.post-7699634070072515732014-01-02T18:11:28.570+05:302014-01-02T18:11:28.570+05:30hello friends, answer key for booklet code C is he...hello friends, answer key for booklet code C is here for physical science<br /><br />http://www.careerendeavour.com/fck/file/ANSWER%20KEY%20DEC-2013/Phy-Answer%20key-Dec-13.pdf<br />ashishhttps://www.blogger.com/profile/18091716461316223358noreply@blogger.comtag:blogger.com,1999:blog-8705083632203739705.post-82190496565640196782014-01-02T12:58:52.329+05:302014-01-02T12:58:52.329+05:30pls check 75th ans once more.. pls check 75th ans once more.. preethihttps://www.blogger.com/profile/16733985315562500103noreply@blogger.comtag:blogger.com,1999:blog-8705083632203739705.post-49941616619601893532014-01-01T15:34:41.834+05:302014-01-01T15:34:41.834+05:30Vin/Vo= 1/wRcVin/Vo= 1/wRcYN8 Blogshttps://www.blogger.com/profile/08039689524585243253noreply@blogger.comtag:blogger.com,1999:blog-8705083632203739705.post-69443316707714456112014-01-01T15:31:51.987+05:302014-01-01T15:31:51.987+05:30what is the condition for being Lx=Ly is not equal...what is the condition for being Lx=Ly is not equal to Lz<br />as far as symmetry ans simultaneity is concern Lx=Ly=LzYN8 Blogshttps://www.blogger.com/profile/08039689524585243253noreply@blogger.com